Question

(URGENT) Someone please help I do not get these questions and I only get one try to insert the correct answer. (IF HELPFUL WILL MARK YOUR ANSWER AS BRAINLIEST)

Answer 1

Answer:

see explanation

Step-by-step explanation:

1

Using right ΔBCD and the tangent ratio to solve for BC

tan40° $\frac{opposite}{adjacent}$ = $\frac{BC}{20}$

Multiply both sides by 20

20 × tan40° = BC

BC ≈ 16.8

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2

Using right ΔABC and the cosine ratio to solve for AB

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{30}{AB}$

Multiply both sides by AB

AB cos30° = 30 ( divide both sides by cos30° )

AB = $\frac{30}{cos30}$ ≈ 34.6

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3

Using the tangent ratio

tanA = $\frac{opposite}{adjacent}$ = $\frac{5}{12}$, hence

A = $tan^{-1}$ ( $\frac{5}{12}$ ) ≈ 22.6°

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4

Using the sine ratio

sin58° = $\frac{4}{x}$

Multiply both sides by x

x sin58° = 4 ( divide both sides by sin58° )

x = $\frac{4}{sin58}$ ≈ 4.7

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5

Any of the 3 trig ratios may be used here since all 3 sides are given.

Using the tangent ratio

tan58° = $\frac{4}{x}$

Multiply both sides by x

x tan58° = 4 ( divide both sides by tan58° )

x = $\frac{4}{tan58}$ ≈ 2.5

Answer 2

Answer:17x - 6 + 3x - 5 = x + 11 + 4x

Step-by-step explanation: