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Alja [10]
3 years ago
12

Match the job skills with the correct job role.

Computers and Technology
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

B-1,A-4,C-2,D-3

Explanation:

You might be interested in
Given the following class, Book, Write code for the following:
Yuri [45]

Using the knowledge in computational language in JAVA it is possible to write a code that can organize the books in price and author classes.

<h3>Writing the code in JAVA we have:</h3>

<em>class Book{</em>

<em>    private int price;</em>

<em>    private String author;</em>

<em>    public Book(int p){</em>

<em>        price=p;</em>

<em>    }</em>

<em>    public Book(Book b){</em>

<em>        price=b.price;</em>

<em>        author=b.author;</em>

<em>    }</em>

<em>    public int getPrice(){</em>

<em>        return price;</em>

<em>    }</em>

<em>    public void setAuthor(String a){</em>

<em>        author=a;</em>

<em>    }</em>

<em>    public String toString(){</em>

<em>        return author+" "+Integer.toString(price);</em>

<em>    }</em>

<em>}</em>

<em>public class Main</em>

<em>{</em>

<em> public static void main(String[] args) {</em>

<em>     Book b=new Book(450);</em>

<em>     b.setAuthor("Jack");</em>

<em>     Book b1=new Book(b);</em>

<em>     System.out.println(b1.toString());</em>

<em> }</em>

<em>}</em>

See more about JAVA at brainly.com/question/18502436

#SPJ1

7 0
2 years ago
a(n) ___ loop allows you to cycle through an array without specifying the starting and ending points for the loop
Arte-miy333 [17]

Answer:

enhanced for loop

Explanation:

Enhanced for loop is an improve concept about loops, this features was implemented in Java SE 5.0 version, this method simplify the For structure. For example:

for (int i = 0; i <array.length; i ++) {  

   System.out.print (array [i]);  

}

Enhanced for loop

for (String element : array) {

   System.out.print(element);

}

8 0
3 years ago
Is mayonnaise technically an instrument?
stich3 [128]
No it doesn’t count as an instrument
7 0
3 years ago
Implement a Java program that creates math flashcards for elementary grade students. User will enter his/her name, the type (+,
jeka57 [31]

import java.util.Scanner;

public class JavaApplication44 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.print("Enter you name: ");

       String name = scan.nextLine();

       System.out.print("Enter your operation (+,-,*,/): ");

       String operator = scan.nextLine();

       System.out.print("Enter the range of the problems: ");

       int ran = scan.nextInt();

       System.out.print("Enter number of problems: ");

       int problems = scan.nextInt();

       int score = 0;

       for (int i = 1; i <= ran; i++){

           int first = (int)(Math.random()*ran);

           int sec = (int)(Math.random()*ran);

           System.out.print("Problem #"+i+": "+first + " "+operator+" "+sec+" = ");

           int ans = scan.nextInt();

           if (operator.equals("+")){

               if (ans == first + sec){

                   System.out.println("Correct!");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first+sec));

               }

           }

           else if(operator.equals("-")){

               if (ans == first - sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first - sec));

               }

           }

           else if (operator.equals("*")){

               if (ans == first * sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first * sec));

               }

           }

           else if (operator.equals("/")){

               if (ans == first / sec){

                   System.out.println("Correct");

                   score++;

               }

               else{

                   System.out.println("Wrong. The correct answer is "+(first / sec));

               }

           }

           

       }

       System.out.println(name+", you answered "+score+" questions correctly.");

   }

   

}

I hope this helps!

8 0
3 years ago
Kristine has been receiving many emails from a certain address. She thinks that these emails might harm her computer. Which acti
Paraphin [41]
Report the email adress then block them 
6 0
3 years ago
Read 2 more answers
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