Answer:
Following are the response to the given question:
Explanation:
Build a spring, sink, vertices, and vertices for each car for a household. Every unit in the stream is a human. Attach the source from each vertical of a family with such a capacity line equivalent to the family size; this sets the number of members in each household. Attach every car vertices to the sink with the edge of the car's passenger belt; this assures the correct number of people for every vehicle. Connecting every vertex in your household to any vertex in your vehicle with a capacity 1 border guarantees that one family member joins a single car. The link between both the acceptable allocation of people to vehicles as well as the maximum flow inside the graph seems clear to notice.
Answer:
3. Paying for my daughter to attend college and building a life outside of struggle. These goals must be accomplished by me finishing school, going onto college and maybe even starting my own business. I must set an appropriate example for my daughter to learn from someone who she believes in. Starting a family business to pass down to generations will be an excellent way to start financially planning now ahead of time.
4. Living in a family of mines, common financial resource is either government assisted or public security.An expense that I cannot escape now is the caring for of my daughter which will vary as she get older. Lastly a debt would be the over spending of credit cards with no money to pay it back as the interest rates climb.
Explanation:
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
<span>Answer: Ring end gap
Ring end gap is the split or gap in the ring. The piston ring is split at one point and it is not completely solid ring and the split/ gap is termed as ring end gap.</span>
