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MrRa [10]
3 years ago
6

Consider the Pythagorean Identity cos 2 ( θ ) + sin 2 ( θ ) = 1 . Divide both sides of this identity by cos 2 ( θ ) and simplify

the resulting equation. What is the result? cos 2 ( θ ) + sin 2 ( θ ) = 1 cot 2 ( θ ) + 1 = csc 2 ( θ ) cos ( θ ) ⋅ sec ( θ ) = 1 1 + tan 2 ( θ ) = sec 2 ( θ )
Mathematics
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

1   +  tan 2θ  = sec 2θ

Step-by-step explanation:

cos 2θ  + sin 2θ   =  1

Dividing  by cos 2θ we get

( cos 2θ  + sin 2θ ) /  cos 2θ   =    1 / cos 2θ

1  +  sin 2θ / cos 2θ   =   sec 2θ

And   sin 2θ / cos 2θ   = tan 2θ

Then

1   +  tan 2θ  = sec 2θ

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One year Thomas had the lowest ERA (earned-run average, mean number of runs yielded per nine inning pitched) of any male pitcher
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Answer:

Thomas had an ERA with a z-score of -2.82.

Karla had an ERA with a z-score of -2.81.

Thomas had the better year compared with his peers, since his ERA had the lower Zscore.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

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The ERA is the Earned Runs Average per 9 innings. This mean that the lower the ERA is, the better it is. So, between Thomas and Karla, whoever has the lower Zscore had the better season.

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For the males, the mean ERA was 4.837 and the standard deviation was 0.541. This means that \mu = 4.837, \sigma = 0.541.

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Z = \frac{X - \mu}{\sigma}

Z = \frac{3.31 - 4.837}{0.541}

Z = -2.82

Thomas had an ERA with a z-score of -2.82.

Karla

For Females, the mean ERA was 4.533 and the standard deviation was 0.539. This means that \mu = 4.533, \sigma = 0.539.

Karla ERA was 3.02. So X = 3.02.

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Karla had an ERA with a z-score of -2.81

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Thomas had the better year compared with his peers, since his ERA had the lower Zscore.

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