Answer:
Total area = 31.5 unit²
Step-by-step explanation:
Assume 1 block = 1 unit²
Divide diagram into 3 part
1. 5 by 5 block square
2. 2 by 2 block triangle(1)
2. 3 by 3 block triangle(2)
Area of square = side × side
Area of square = 5 × 5
Area of square = 25 unit²
Area of triangle(1) = [1/2][base][height]
Area of triangle(1) = [1/2][2][2]
Area of triangle(1) = 2 unit²
Area of triangle(2) = [1/2][base][height]
Area of triangle(2) = [1/2][3][3]
Area of triangle(2) = 4.5 unit²
Total area = Area of square + Area of triangle(1) +Area of triangle(2)
Total area = 25 unit² + 2 unit² + 4.5 unit²
Total area = 31.5 unit²
The total area is:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
We have then:
For the base area:
Ab = (2) * (2)
Ab = 4 units ^ 2
For the lateral area:
Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
Al = (4) * (root (1 + 9))
Al = 4raiz (10) units ^ 2
Total area:
A = 4 + 4raiz (10)
Answer:
A = 4 + 4raiz (10)
Domain: all real numbers
Range: y<0
96 Degrees.You need to find the length of the arcs outside by multiplying the inside angles by 2. That number must go with the arcs that are enclosed.
