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Doss [256]
3 years ago
15

The original value of a car is $18,000, and it depreciates (loses value) by 15% each year. What is the value of the car after th

ree years?
Mathematics
1 answer:
Sliva [168]3 years ago
6 0
A reduction of 15% per year means 100-15=85% reducing factor.
1st year: 0.85×18000=$15300.
2nd year: 0.85×15300=$13005.
3rd year: 0.85×13005=$11054.25.
So after 3 years the value of the car is $11054.25 or $11054 to the nearest dollar.
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Step-by-step explanation:

Let x = the number of years since the first year and let y = the total number of plants.

Roses: y = 5 + 2x

Tulips: y = 20 – 3x

You can use elimination to solve.

y = 5 + 2x

(-)y = 20 – 3x

0 = -15 + 5x

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This means that 3 years after the first year, the number of rose bushes equals the number of tulip plants.

The graphs appear to

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3 years ago
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(-4,1)

Step-by-step explanation:

for x you do:

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3 years ago
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Answer:

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We are given:

y = 9

Putting value in y = r sin Ф

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=> r = 9/sin Ф

1/sin Ф = csc Ф

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Use the table to write a liner function that relates to y to x X: -2, 0, 2, 4
Contact [7]
I think this is the answer
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8 0
3 years ago
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Answer:

x <= 9

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