Ask question

Ask question

All categories

3 years ago

5

Help asap!! There’s a photo

1 answer:

tester [92]3 years ago

4 0

Answer:

C

Step-by-step explanation:

The vertex form for a parabola is a(x-h)^2 + k, where h is the x coordinate of the vertex and k is the y coordinate. a represents the amount that the graph has been "squeezed". Therefore, since the coordinates of the vertex of this parabola are (2,4), and it is "squeezed" by a factor of 2, the correct answer is C. Hope this helps!

You might be interested in

1 over 8 + c = 4 over 5 whats x?

Alex Ar [27]

Answer:

c=27/40 = 0.675

Step-by-step explanation:

the statement give us the expression:

1/8 +c= 4/5

we subtract the term "1/8" both sides:

we have:

1/8 -1/8+c= 4/5-1/8

c=4/5-1/8

c=(4*8)-(5*1)/(5*8)

c=(32-5)/(40)

c =27/40 = 0.675

3 0

3 years ago

Read 2 more answers

URGENTTT PLEASE HEEEEELP

Mashcka [7]

Answer:

1)

M: 15

T: 14

W: 19

Th: 20

F: 9

Sa: 9

Su: 5

2) 18 degrees

Step-by-step explanation:

4 0

3 years ago

PLZ HELP URGENT PLEASE

alexira [117]

Answer should be 4x+2

6 0

3 years ago

What is the surface area for this?

chubhunter [2.5K]

look on Google for the answers

4 0

3 years ago

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12

Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

$P(x)=-12x^2+120x$

To find:

The current that will produce the maximum power.

Solution:

We have,

$P(x)=-12x^2+120x$

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, a=-12 and b=120. So,

$-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}$

$-\dfrac{b}{2a}=-\dfrac{120}{-24}$

$-\dfrac{b}{2a}=5$

Putting x=5 in the given function, we get

$P(5)=-12(5)^2+120(5)$

$P(5)=-12(25)+600$

$P(5)=-300+600$

$P(5)=300$

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0

3 years ago