Since ABC is a 90-60-30 triangle, it is half of an equilateral triangle. This means that BC is half AC, i.e. 17.
So, we have
![AB = \sqrt{AC^2-BC^2}=\sqrt{AC^2-\left(\dfrac{AC}{2}\right)^2}=\dfrac{\sqrt{3}}{2}AC = \sqrt{3}\cdot BC =\sqrt{3}\cdot 17\approx 29.4](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7BAC%5E2-BC%5E2%7D%3D%5Csqrt%7BAC%5E2-%5Cleft%28%5Cdfrac%7BAC%7D%7B2%7D%5Cright%29%5E2%7D%3D%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7DAC%20%3D%20%5Csqrt%7B3%7D%5Ccdot%20BC%20%3D%5Csqrt%7B3%7D%5Ccdot%2017%5Capprox%2029.4)
So, the perimeter is
![AD+DC+BC+AB\approx34+34+17+29.4\approx 114.4](https://tex.z-dn.net/?f=AD%2BDC%2BBC%2BAB%5Capprox34%2B34%2B17%2B29.4%5Capprox%20114.4)
Length = x - 2
Width = x - 5
Explanation:
Area = x^2 - 7x + 10
Area = (x - 2)(x - 5)
Area = Length x Width
Length = x - 2
Width = x - 5
In order to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%.
Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%
The million doesn't matter.
Answer:
D
Step-by-step explanation:
D