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3 years ago

The question is down below

Mathematics

1 answer:

melisa1 [442]3 years ago

8 0

The answer is 'A'

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago

What is the answer A, B, C, or D

adell [148]

The answer would have to be

7 0

3 years ago

Math. please help me!!!

d1i1m1o1n [39]

Part A.

In this part we have to find the increasing interval .

Increasing interval is that interval where graph goes up. And from the graph we can say that the graph goes up in the interval

$(-1,0)U (1, \infty)$

And that's the increasing interval .

Part B.

Correct option is B

x and y intercepts

x intercept is the point where graph touches the x axis. And the graph touches the x axis at x=-1 and 1 .

So the x intercepts are

$(-1,0) ,(1,0)$

y intercepts are the point, where the graph touches or crosses the y axis.

Therefore the y intercept is (0,1)

So the correct option is D .

4 0

3 years ago

Read 2 more answers

Help me with (d)(ii).<br><br> Thank you!

lord [1]

$q=\frac{h^{2}-k^{2}}{3m}$
Cross-multiplying and rearranging, we get:
$k^{2}=h^{2}-3mq$
or written without using latex:
k^2 = h^2 - 3mq
Can you finish now?

4 0

3 years ago

Charmaine is fertilizing her garden. The garden is in the shape of a rectangle. Its length is 12 feet and its width is 10 feet.

Nana76 [90]

Answer:

4 bags

Step-by-step explanation:

lxw

12x10=120

30x4=120

l=length

w=width

6 0

3 years ago