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kolezko [41]
2 years ago
7

Using the equation x+3, write one equation that has one solution, one equation that has no solution, and one equation that has i

nfinitely many solutions
Mathematics
1 answer:
neonofarm [45]2 years ago
8 0

9514 1404 393

Answer:

  • one: x+3 = 2x
  • none: x+3 = x
  • infinite: x+3 = x+3

Step-by-step explanation:

A linear equation with variable terms on opposite sides of the equal sign will have one solution when the coefficients of those variables are different.

  x+3 = 2x . . . . has one solution (x=3)

__

There will be no solution if the variable terms on opposite sides of the equal sign have the same coefficient, but the constants are different. Such an equation can be reduced to 0 = 1, which cannot be made true by any value of the variable.

  x +3 = x . . . . has no solutions

__

There will be an infinite number of solutions if the left side of the equal sign is the same as the right side. Every value of the variable will satisfy the equation.

  x +3 = x +3 . . . . has infinite solutions

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Answer:

Step-by-step explanation:

L=2W

P=2(L+W), using L=2W this becomes

P=2(2W+W)

P=2(3W)

P=6W, given P=150

6W=150

W=25, and since L=2W

L=50 so

L=50ft and W=25ft

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A rectangular bathroom mirror is 4 feet wide and 2 feet tall. What is its perimeter?
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What changes would you make in your description of point, line, and plane?
weeeeeb [17]

Answer:

Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)

P

=

(

x

1

,

y

1

,

z

1

)

to a plane determined by normal vector N=(A,B,C)

N

=

(

A

,

B

,

C

)

and point Q=(x0,y0,z0)

Q

=

(

x

0

,

y

0

,

z

0

)

. The equation for the plane determined by N

N

and Q

Q

is A(x−x0)+B(y−y0)+C(z−z0)=0

A

(

x

−

x

0

)

+

B

(

y

−

y

0

)

+

C

(

z

−

z

0

)

=

0

, which we could write as Ax+By+Cz+D=0

A

x

+

B

y

+

C

z

+

D

=

0

, where D=−Ax0−By0−Cz0

D

=

−

A

x

0

−

B

y

0

−

C

z

0

.

This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P

P

.

Step-by-step explanation:

5 0
2 years ago
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