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ZanzabumX [31]
3 years ago
5

Arrange the steps in the correct order to perform this subtraction problem 1.1 ( 10 3 ) − 4.9 ( 10 2 ) = 610

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

We are given :  Expression 1.1 ( 10^3 ) − 4.9 ( 10^2 ) = 610.

Solution: In order to solve above given expression, we need to apply order of operations.

We can apply order of operations according to PEMDAS rule.

PEMDAS stands for Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.

In the given problem, we need to simplify Parentheses first.

We have 10^3 and 10^2 in Parentheses.

10^3 = 10*10*10 = 1000.

10^2 = 10*10 = 100.

Substituting those values in original expression.

1.1 ( 1000 ) − 4.9 ( 100 ).

Now, we need to apply multiplication operation in 1.1*1000 and 4.9*100.

We get 1.1*1000 = 1100 and 4.9*100 = 490.

Substituting those values in above result we got.

1100-490.

Now, we can perform subtraction operation.

On subtracting 1100-490, we get 610.

And that is equal to 610.



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The answer to your question is:

Domain [0, 8)

Range [-3, 1]

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Step-by-step explanation:

Domain: is the possible values that the "x" can take

Range: are the values that take the function when is evaluated by the independent variable (x).

For this example:

                            Domain [0, 8)   close is zero and open in 8

                            Range [-3, 1]     close in both sides

                           f(0) = -3

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Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

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