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3 years ago

The total area of Fred's yard is 60 square feet. The length is 6 feet. What is the width?

Mathematics

2 answers:

inysia [295]3 years ago

7 0

Answer:

Step-by-step explanation:

Savatey [412]3 years ago

7 0

Answer:

10 square feet

Step-by-step explanation:

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What is the highest common factor of 36 and 56???

Orlov [11]

Answer:

The highest common factor of 36 and 56 is number6

5 0

3 years ago

Read 2 more answers

1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago

Simplify. write your answer in standard form. <br> -4-8x+2x-15

ValentinkaMS [17]

Answer:

x=2

Step-by-step explanation:

3 0

4 years ago

I forgot to do slopes

Minchanka [31]

To find the slope of the line, use the rise over run formula:

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Take any two points from the line and plug them into the formula.

(0,0) and (10, 5)

$\frac{5 - 0}{10 - 0} = \frac{5}{10} = 0.5$

The slope of the line is 0.5.

Using the form y = mx, the following equation will be your answer:

$y = 0.5x$

7 0

3 years ago

The area of a rectangle is 84 square inches. the length of the rectangle is 2 longer than twice the width. find the width and th

IgorC [24]

Let l = the lentth of the rectangle and w = the width of the rectangle; where w>0 and l>0;
We have 84 = l x w and l = 2 + w;
84 = (2+w) x w;
We solve the equation: w^2 + 2w - 84 = 0;
We obtain the solution w = 8.21;
The perimeter of the triangle is is 3 x 8.21 = 24.63;

8 0

3 years ago