What is the cross section formed by a plane that intersects three faces of a cube
1 answer:
You might be interested in
Check the picture below.
now, if AC is that much, recall, BD is the midsegment, thus AB = BC, so AB is just one of the equal halves of AC, so, AB is AC/2.
now, if AC is that much, recall, BD is the midsegment, thus AB = BC, so AB is just one of the equal halves of AC, so, AB is AC/2.
Answer:
Step-by-step explanation:
If x varies directly as the product of p and m, and inversely with y, the relation can be written ...
x = k(pm)/y . . . . where k is the constant of proportionality
__
This can be solved for k:
k = xy/pm
For the given values, the value of k is ...
k = (2)(4)/((0.5)(2)) = 8
Then the relation between the variables can be written ...
(xy)/(pm) = 8