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vampirchik [111]
3 years ago
12

Find the number z, if 1 4/11 of z is 45. (FIRST PERSON TO ANSWER CORRECTLY GETS 5 STARS AND A THANKS.)

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

The value of z in the equation 1\frac{4}{11} of z is 45 is 33.

<u>Solution:</u>

Given: 1\frac{4}{11} of z = 45

To find: The value of z

On solving the given equation,

1\frac{4}{11}\times z=45

\Rightarrow\frac{1\times11+4}{11}\times z=45

\Rightarrow\frac{15}{11}z=45

On grouping the like terms in one side we get,

\Rightarrow z=45\times\frac{11}{15}

On solving the values we get,

\Rightarrow z=3\times11\rightarrow33

The required value of z is 33.

<u>Steps to convert a mixed fraction into an improper fraction:</u>

Step 1: Multiply the whole number part by the fraction's denominator.

Step 2: Add that to the numerator.

Step 3: Then write the result on top of the denominator.

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olga2289 [7]

Answer:

a) 2.5 pounds of candy

b) 2.5 pounds of candy

    \frac{0.5}{1} :\frac{y}{5}

    y × 1 = 0.5 × 5

    y = 2.5

Step-by-step explanation:

1 = 5

1/2 = y or 0.5 = y

\frac{0.5}{1} :\frac{y}{5}

y × 1 = 0.5 × 5

y = 2.5

7 0
3 years ago
Students were asked to write 6x5 + 8x - 3x3 + 7x7 in standard form.
dimulka [17.4K]

Answer:

7x^{7} + 6x^{5} - 3x^{3} + 8x

Step-by-step explanation:

Students are asked to write 6x^{5} + 8x - 3x^{3} + 7x^{7} in the standard form.

Now, in the standard form of a polynomial the highest power of the variable takes the leftmost position and the lowest power of the variable takes the rightmost position and the power of variable decreases from left to right.

Therefore, the standard form will be 7x^{7} + 6x^{5} - 3x^{3} + 8x. (Answer)

3 0
3 years ago
Solve for x. √x−11=5
kkurt [141]
X = 126

HOPE THIS HELPS!!!!!!!! :D
5 0
3 years ago
Solve algebraically for x and explain each step( using mathematical vocbuary) for the following: 2(x+5)+ 3x = 30
Lelu [443]
First do distributive property
2x + 10 + 3x = 30
Now combine like terms
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Subtract 10 from both sides
5x = 20
Divide both sides by 5
x = 4
8 0
3 years ago
Please Help Me ASAP!!!
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Everything you need is in the picture attached.

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