Answer:
As the points are collinear, the slope of the line joining
any two points, should be same as the slope of the line joining two other
points.
Slope of the line passing through points (x
1
,y
1
) and (x
2
,y
2
) =
x
2
−x
1
y
2
−y
1
So, slope of the line joining (p,0),(0,q)= Slope of the line joining
(0,q) and (1,1)
0−p
q−0
=
1−0
1−q
−
p
q
=1−q
Dividing both sides by q,
−
p
1
=
q
1
−1
=>
p
1
+
q
1
=1
Answer:
a
Step-by-step explanation:
<u>Answer</u>
12 units
<u>Explanation</u>
This can be solved using the properties of a circle.
DG and EG are secants f the circle.
DG×HG =EG×FG
(x+3+5)×5 = (x+6)×6
(x+8)5 = 6x + 36
5x +40 = 6x + 36
x = 4
DG = (x+3+5)
= 4 + 3 + 5
= 12 units
Answer:
x =-4
Step-by-step explanation:
3x − 7 = −19
Add 7 to each side
3x − 7+7 = −19+7
3x = -12
Divide by 3
3x/3 = -12/3
x =-4