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3 years ago

Find the slope of the line through each pair of points.

Mathematics

1 answer:

Fudgin [204]3 years ago

7 0

<h2>Answer: slope = ¹¹/₁₃ </h2><h3>Step-by-step explanation: </h3>

The question gives us two points, (−13, −19) & (13, 3), from which we can find the slope and later the equation of the line.

Finding the Slope

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)

= ((3 - (-19)) ÷ (13 - (-13))

= 22 ÷ 26

= ¹¹/₁₃

Checking my answer:

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line. If the line passes through both of the points then we calculated the slope correctly.

⇒ y + 19 = ¹¹/₁₃ (x + 13)

I have included a Desmos Graph that I graphed using the information equation (including the slope) and the points given.

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Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0

3 years ago

Volume 918 yd. what is volume in ft

vitfil [10]

918yd³= 24786.00ft³

i believe that's what you were looking for?

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3 years ago

How deep the water 50 ft from the shore ?

PIT_PIT [208]

400 ft. Hope it helps. Pls Give brainliest answer!

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3 years ago

What is the area of a gameboard if it is 9 1/2 inches by 11 3/4 inches

Reil [10]

You just need to multiply 9 1/2 by 11 3/4. simplify these into decimals: 9.5 and 11.75

Then do 9.5*11.75=111.625

4 0

4 years ago

A 15-foot ladder leans against a house. The bottom of the ladder is 7 feet from the house. To the nearest degree, what angle doe

max2010maxim [7]

The ladder is forming a right triangle with the house. In this right triangle the hypotenuse is the measure of the ladder, and the distance between the house and he ladder is one of the sides of the triangle. To find the angle, $\alpha$ , that the ladder is making with the ground, we are going to use a trig function that relates the adjacent side of our angle with the hypotenuse. That trig function is Cosine.
$Cos \alpha = \frac{adjacent.side}{hypotenuse}$
$Cos \alpha = \frac{7}{15}$
$\alpha =arcCos( \frac{7}{15} )$
$\alpha =62.2$

We can conclude that the ladder make with the ground a 62° angle.

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3 years ago