10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
An example of Algebra structure work is simplify (8-3)+3.
<h3>What is algebraic structure?</h3>
In mathematics, an algebraic structure is known to be a term that is made up of a nonempty set A, a combination of operations on A of finite series and a finite group of identities.
To simply this equation, (8-3)+3.
One has to follow the order of operations using the P.E.M/D.A/S technique, the expression that are in the parenthesis have to be solved first.
2 of 3
(5)+3 = 8
Therefore, the answer is 8
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Metals are found in group 1, 2, and abit of 3.
Non-metals are found in group 0/8, abit in 4, 5, 6 and 7 too. Here is a picture. Most of the periodic table are metals.