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Rzqust [24]
3 years ago
5

They won 3 out of every 4 home games and 2 out of every 3 away game. All together they won 40 more games than they lost. If they

played as many home games as away games, what was their final record of wins and losses?
Mathematics
1 answer:
lina2011 [118]3 years ago
5 0

See https://web2.0calc.com/questions/help-please_82538.

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At the beginning of football season, Coach Carnes takes inventory of the team equipment to see what he needs. He counts 24 footb
Leviafan [203]

Answer:

13

Step-by-step explanation:

To solve this, lets first find the number of footballs he still needs:

75-24 = 51

Now to find the number of packages, divide by 4, since there are 4 balls per package:

51/4 = 12 Remainder 3

Since there is a remainder, and the Coach MUST have at least 75, then we need to add a package to include the remainder:

12 + 1 = 13 Packages

6 0
3 years ago
I'm so confused, pls help
Vera_Pavlovna [14]

Answer:

x = 14      D

Step-by-step explanation:

(18x + 36) / 3 = 6x + 12

6x + 12 = -16 + 8x

-6x .                -6x

12 = -16 + 2x

+16 . +16

28 = 2x

/2 .   /2

14 = x

8 0
2 years ago
HELP PLZ NEED HELP SHOW WORK TOO
monitta
15.        3x - 2y = -2
      3x - 3x - 2y = -3x - 2
                   -2y = -3x - 2
                    -2         -2
                       y = 1.5x + 1

y - y₁ = m(x - x₁)
 y - 3 = ⁻²/₃(x - (-2))
 y - 3 = ⁻²/₃(x + 2)
 y - 3 = ²/₃(x) - ²/₃(2)
 y - 3 = ⁻²/₃x - 1¹/₃
   + 3            + 3
       y = ⁻²/₃x + 1²/₃

16. 230 = 0.2s + 150
    - 150             - 150
        80 = 0.2s
        0.2    0.2
      400 = s

17. y = 2x + 2
5 0
3 years ago
I don’t know how to do it, please teach me !!!
cricket20 [7]

As described in z-distribution the answers are given below:

a) The 95% confidence interval estimate for the population mean spending by a customer on visiting salon per month is given as follows: (747, 853).

b) The sampling error at 95% confidence level is of: $35.78.

What is a z-distribution ?

The normal distribution with a mean of 0 and a standard deviation of 1 is referred to as the standard normal distribution (also known as the Z distribution) (the green curves in the plots to the right). It is frequently referred to as the bell curve since the probability density graph resembles a bell.

solution:

The bounds of the confidence interval are given as follows:

In which:

is the sample mean.

z is the critical value.

n is the sample size. is the standard deviation for the population.

The parameters for this problem are given as follows:

Hence the lower bound of the interval is of:

800 - 200 x 1.96/square root of 55  = 747.

The upper bound of the interval is of:

800 + 200 x 1.96/square root of 55  = 853.

The sampling error for a sample size of 120 is calculated as follows:

200 x 1.96/square root of 120 = $35.78.

To learn more about the z-distribution from the given link

brainly.com/question/4079902

#SPJ1

5 0
1 year ago
What is 28.6 - 0.975 and I need an explanation.
bekas [8.4K]
The answer is 27.625 !

hope this helpss !!
8 0
3 years ago
Read 2 more answers
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