Answer:
-18/32
Step-by-step explanation:
I multiplied the fraction by 2/2 to get another fraction that equals -9/16
Yes, it is 110%, hope that helps!
ANSWER
![\theta =73.2 \degree](https://tex.z-dn.net/?f=%20%5Ctheta%20%3D73.2%20%5Cdegree)
EXPLANATION
We use the sine rule to obtain,
![\frac{ \sin( \theta) }{4} = \frac{ \sin(50 \degree) }{3.2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B%20%5Csin%2850%20%5Cdegree%29%20%7D%7B3.2%7D%20)
We multiply both sides by 4 to obtain,
![\sin( \theta) = \frac{ \sin(50 \degree) }{3.2} \times 4](https://tex.z-dn.net/?f=%20%5Csin%28%20%5Ctheta%29%20%3D%20%20%5Cfrac%7B%20%5Csin%2850%20%5Cdegree%29%20%7D%7B3.2%7D%20%20%5Ctimes%204)
We take the inverse sine of both sides to get,
![\theta = \sin ^{ - 1} (0.9576)](https://tex.z-dn.net/?f=%20%5Ctheta%20%3D%20%20%5Csin%20%5E%7B%20-%201%7D%20%280.9576%29%20)
![\theta =73.2](https://tex.z-dn.net/?f=%20%5Ctheta%20%3D73.2)
to the nearest tenth.
Answer:
d = 7
Step-by-step explanation:
Distance Formula: ![d = \sqrt{(x2 - x1)^2+(y2-y1)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x2%20-%20x1%29%5E2%2B%28y2-y1%29%5E2%7D)
Plug in our 2 coordinates:
![d = \sqrt{(2-2)^2+(1+6)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%282-2%29%5E2%2B%281%2B6%29%5E2%7D)
And you should get 7 as your final answer.
If you are asking which one is false, it is all quadrilaterals are trapezoids.