Answer:
Mixture problemsare ones where two different solutions are mixed together ... should be added to the first in order to get amixture of 5% salt?4) How much ... 8 6) How many grams of pure acid must be added to 40 grams of a 20% acidsolution to ... make a Mixture that perliter?15) Solution A is 50% acid and solution B is 80% ...
Step-by-step explanation:
Answer:
the answer is b
HOPE THIS HELPS
Step-by-step explanation:
144 cm^2
Bottom 32 + slant 40 + 2 sides 24 each + back 24
Answer:
yes it does
pls give brainly
Step-by-step explanation:
I hope this helps you
xy=-6 y=-6/x
2y-x=8
-x+2.-6/x=8
-x^2-12=8x
x^2+8x+12=0
(x+6). (x+2)=0
x+6=0 x=-6
x+2=0 x=-2
x=-6 -6.y=-6 y=1
x=-2 -2.y=-6 y=3
