Lim[x.sin(4π/x)] when x →∞. To apply the Hospital rule we need a fraction:
lim[x.sin(4π/x)] could be written:
lim [sin(4π/x)] / (1/x) . Now let's find the derivative of the numerator and the denominator:
Numerator = sin(4π/x) → (Numerator)' = cos(4π/x).(-4π/x²) [Chaine rule
(sinu)' = cosu. u'] So derivative of Numerator = cos(4π/x).(-4π/x²)
Denominator = 1/x → Numerator derivative = -1/x²
Now : (numerator)'/(denominator)' = cos(4π/x).(-4π/x²) / -1/x²
Simplify by x² : → cos(4π/x).(-4π) / -1
OR cos(4π/x).(4π) . When x→∞ , 4π/x → 0 and cos(0) = 1, then:
lim[x.sin(4π/x)] when x →∞. is 4π
20.7123152 thats the answer i looked it up
Answer:
sorry if I get this wrong but I think it's a or c
Step-by-step explanation:
hope this helps
Answer:
Step-by-step explanation:
If there are 90 students and the ratio of boys to girls is 3:2, that means 3x+2x=90
Combine like terms: 5x=90
x=18
2x (girls)=36
3x (boys)=54
1/3 of the boys scored full marks, so 54/3=18 boys scored full marks
The number of girls who scored full marks is half of the number who did not score full marks means that 1/3 of the girls scored full marks. 36/3=12, so 12 girls scored full marks.
(I don't know what the question is sorry if it's incorrect but there's not enough information)
Hope this helps!