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vazorg [7]
3 years ago
10

What is the surface area of a sphere with a radius of 12 units?

Mathematics
2 answers:
irina1246 [14]3 years ago
7 0

Answer: 576 (pie)units^2

Step-by-step explanation: APEX

Brrunno [24]3 years ago
6 0
Sphere Surface Area     =    <span> 4 • <span>π <span>• r²
</span></span></span>
Sphere Surface Area     = <span> <span> <span> 1,809.5573684677 </span>


</span> </span>
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Which equation shows y+1/5=3x in standard form?
zhannawk [14.2K]
I believe the correct answer is 15x + 5y =-1 but im not positive cause i did the problem and got -1 but the equation i got looks different i got the equation -15x + 5y = -1
These are the steps i followed
You always begin by the Given equation, which is in this case:
y+ = 3x
To remove the fraction, you multiply the whole equation by 5:
5y + 1 = 15x
Then, you move the "15x" the left-side of the equation, changing it's sign
-15x + 5y +1 = 0
You move the "1" to the right side, changing it's sign
-15x + 5y = -1
4 0
4 years ago
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If P = (-1,6), Find: Rx-axis (P).
Hatshy [7]

Answer:

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7 0
3 years ago
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Verify sin^4 x - sin^2 x = cos^4 x - cos^2 x is an identity
Citrus2011 [14]

Answer:

(identity has been verified)

Step-by-step explanation:

Verify the following identity:

sin(x)^4 - sin(x)^2 = cos(x)^4 - cos(x)^2

sin(x)^2 = 1 - cos(x)^2:

sin(x)^4 - 1 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

-(1 - cos(x)^2) = cos(x)^2 - 1:

cos(x)^2 - 1 + sin(x)^4 = ^?cos(x)^4 - cos(x)^2

sin(x)^4 = (sin(x)^2)^2 = (1 - cos(x)^2)^2:

-1 + cos(x)^2 + (1 - cos(x)^2)^2 = ^?cos(x)^4 - cos(x)^2

(1 - cos(x)^2)^2 = 1 - 2 cos(x)^2 + cos(x)^4:

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = ^?cos(x)^4 - cos(x)^2

-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = cos(x)^4 - cos(x)^2:

cos(x)^4 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2

The left hand side and right hand side are identical:

Answer:  (identity has been verified)

3 0
3 years ago
If you want to know the probability of spinning a spinner in a game that has 8 equal-sized
aleksandr82 [10.1K]

the answer is 1/8. Because you divide how many pieces there are by that same number.

7 0
3 years ago
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What are the coordinates of the point that is common to the graph of f(x) = (2/3) ^ x and the graph of f(x) = (3/2) ^ x
kiruha [24]

Answer:

Both point are y=0. The difference between the two is that 2/3 is always decressing and 3/2 is always incressing.

Step-by-step explanation:

7 0
2 years ago
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