Question

Find the derivative of the function.. y = cot2(sin θ).

Answer 1

Y' = 2 cot ( sin t ) * derivative of cot ( sint t) 
 2 cot(sin t) * [- cosec^2 (sin t)] * derivative of sin t 
 -2 cot( sin t) cosec^2( sin t) * cos t

Answer 2

Y = cot2(sinФ)
dy/dФ = d/dФcot2(sinФ)
 dy/dФ = -cosec²2(sinФ) d/dФ2(sinФ)
dy/dФ = -cosec²2(sinФ) 2cosФ
dy/dФ =-2[cosФ][cosec²2(sinФ)]