Find the derivative of the function.. y = cot2(sin θ).

2 answers:

7 0

Y' = 2 cot ( sin t ) * derivative of cot ( sint t)
<span> 2 cot(sin t) * [- cosec^2 (sin t)] * derivative of sin t </span>
<span> -2 cot( sin t) cosec^2( sin t) * cos t</span>

lana66690 [7]4 years ago

6 0

Y = cot2(sinФ)
dy/dФ = d/dФcot2(sinФ)
dy/dФ = -cosec²2(sinФ) d/dФ2(sinФ)
dy/dФ = -cosec²2(sinФ) 2cosФ
dy/dФ =-2[cosФ][cosec²2(sinФ)]

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Answer:

Step-by-step explanation:

hello :

the sequence 9,-18,36 is geometric when the common ratio is:

r= 36/-18=-18/9=-2

let (An) this sequence the n-ieme term is : An=A1×r^(n-1).....A1=9 and n=9

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