Answer:
3. 15 units
Step-by-step explanation:
When medians intersect, the point of intersection divides the median into parts in the ratio 2:1. That is ...
OC : CR = 2 : 1 = 4 units : 2 units . . . . . . OR = (4+2) units = 6 units
MC : CT = 2 : 1 = 6 units : 3 units . . . . . . MT = (6+3) units = 9 units
The sum of lengths OR + MT is ...
6 units + 9 units = 15 units
Answer:
120 minutes
Step-by-step explanation:
hope this will help :)
Answer:
-a² + 2ab + b² is your answer, or C).
Step-by-step explanation:
b(a + b) -a (a - b)
Distribute b to (a + b), and -a to (a - b)
b(a + b) = ab + b²
-a(a - b) = -a² + ab
Simplify. Combine like terms.
(-a² + ab) + (ab + b²) = -a² + 2ab + b²
-a² + 2ab + b² is your answer, or C).
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Let the number of bags of feed type I to be used be x and the number of bags of feed type II to be used be y, then:
We are to minimize:
C = 4x + 3y
subject to the following constraints:

From the graph of the 4 constraints above, the corner points are (0, 5), (1, 2), (4, 0).
Testing the objective function for the minimum corner point we have:
For (0, 5):
C = 4(0) + 3(5) = $15
For (1, 2):
C = 4(1) + 3(2) = 4 + 6 = $10
For (4, 0):
C = 4(4) + 3(0) = $16.
Therefore, the combination that yields the minimum cost is 1 bag of type I feed and 2 bags of type II feed.
N would be the variable that we are solving for.
Lets solve:-
n * 3.25 = 325
3.25/3.25 = 325/3.25
n = 100
Answer: n = 100