Answer: infinite solutions
Step-by-step explanation:
(−3) (4) + (−3) (−3x) = 9x + −12
−12 + 9x = 9x + −12
9x − 12 = 9x − 12
9x − 12 − 9x = 9x − 12 − 9x
−12 = −12
−12 + 12 = −12 + 12
0 = 0
Answer:
No, the student is not correct. The correct expression is 9(n+13).
Step-by-step explanation:
"9 times the sum of a number and 13" means you must multiply 9 by the sum, not just by the number. 9n + 13 would be "the sum of 9 times a number and 13." Slightly different wording.
Solving for x.
Since x<span> is on the right-hand side of the </span>equation<span>, switch the sides so it is on the left-hand side of the </span>equation<span>.
</span><span>0.04<span>x2</span>−8.504x+25302=c
</span>Simplify the quadratic and set<span> the right side equal to </span><span>0.
</span><span>0.04<span>x2</span>−8.504x+25302−c=0
</span>Use the standard form of the quadratic <span>(<span><span>a<span>x2</span>+bx+c</span>)</span></span><span> to find </span><span>a,</span><span>b,</span><span> and </span>c<span> for this quadratic.
</span><span>a=0.04,</span><span>b=−8.504,</span><span>c=25302−1c
</span>Use the quadratic formula<span> to find the </span>solutions<span>.
</span><span>x=<span>−b ± </span></span>√<span><span> <span><span>b2</span>−4ac /</span> </span><span>2a
</span></span>Substitute in the values of <span><span>a=0.04</span>,</span><span><span>b=−8.504</span>,</span><span> and </span><span><span>c=25302−1c</span>.
</span>x=<span>−(−8.504) ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
<span>Simplify.
</span>x=<span>8.504 ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
Simplify the section inside the radical<span>.
</span>x=<span>8.504 ± </span>√<span><span><span>−3976.001984+0.16c</span>/</span><span>2(0.04)
</span></span>
Simplify the denominator<span> of the </span>quadratic formula<span>.
</span>x=<span>8.504 ±</span>√<span><span>−3976.001984+0.16c/</span>0.08
</span>
Answer:
x=8.504 ±√−3976.001984+0.16c/0.08
D. The length is 32 inches and the width is 40 inches
Original Circle Area = 45
A = pi * r^2
Plug in what we know:
45 = 3.14 * r^2
Divide 3.14 to both sides:
14.3312102 = r^2
Find the square root of both sides:
r = 3.78565849
Find 2/3 of this:
2/3 * 3.78565849 = 2.52377233
So this is the radius of the newly dilated circle.
A = pi * r^2
A = 3.14 * 2.52377233^2
A = 3.14 * 6.36942677
A = 20
So the area of the newly dilated circle is 20 square inches.