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svetlana [45]
4 years ago
14

Ya'll please help me!!!!. The water was pumped out of a backyard pond, What is the domain of this graph????

Mathematics
2 answers:
saw5 [17]4 years ago
6 0
Stuck on the same question and it looks like nobody cares to answer on this website
OleMash [197]4 years ago
3 0

Answer:

A. Real numbers from 0 to 8.

Step-by-step explanation:

Since, the given graph represents the depth of water pumped out of the backyard pound,

So, time ( in minutes ) must show the input value and depth ( in inches ) must show the output value,

Also, by the given graph,

Time is defined from 0 to 8 minutes,

Thus, the possible input values of the function of the graph are all the real number between 0 to 8,

Now, we know that the set of all possible input values is called domain of the function,

Hence, the domain of the given graph is,

Real numbers from 0 to 8.

Option 'A' is correct.

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Write the expression as a product of two factors: 6m + 8n + 4
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mafiozo [28]
Ok, so dy/dx=0 at the point (0,3) that is where x=0 and y=3.

\int { 6x+6dx } \\ \\ =\frac { 6{ x }^{ 2 } }{ 2 } +6x+C\\ \\ =3{ x }^{ 2 }+6x+C

\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x+C

Now, f'(x)=0 when x=0.

Therefore:

0=C\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x

Now:

\int { 3{ x }^{ 2 } } +6xdx\\ \\ =\frac { 3{ x }^{ 3 } }{ 3 } +\frac { 6x^{ 2 } }{ 2 } +C

={ x }^{ 3 }+3{ x }^{ 2 }+C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+C

But when x=0, y=3, therefore:

3=C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+3
7 0
3 years ago
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Find the expression that represents the<br> value of v.<br> 2(v - 8) = n+y
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Answer:

v = \frac{n+y+16}{2}

Step-by-step explanation:

2(v-8) = n+y

Distribute

2v-16 = n+y

Move -16 to the other side

2v = n+y+16

Divide everything by 2

v = \frac{n+y+16}{2}

4 0
2 years ago
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