My son is seven times older than my grandson and I am 12 times older than my grandson. If you add all our ages together, the sum
1 answer:
You might be interested in
Answer: 11.6
--------------------------------------
Explanation:
See the attached image for a visual reference
The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)
We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is
AD = x
Because AD is another radius of the same circle
Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to 11.6 when rounding to the nearest tenth (one decimal place)
--------------------------------------
Explanation:
See the attached image for a visual reference
The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)
We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is
AD = x
Because AD is another radius of the same circle
Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to 11.6 when rounding to the nearest tenth (one decimal place)
Answer:
Small candies
Extra large candies
Step-by-step explanation:
Let small candies
Extra large candies
the number of candies is at least .
Cost of small candy
Cost of extra large candy
but she has only to spend
Solve for
Since number of candies should be integer.
let
total spend which is more than
, so this combination is not possible.
She has more so she can buy
more small candy.
Hence small candy
extra large candy