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3 years ago

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1. Find the values of X and Y.

1 answer:

Andrei [34K]3 years ago

4 0

156 and (14y+30) are opposite angles so they are the same. You can use this information to put them into an equation to solve;

14y+30 = 156
You want you the the y's alone, so you subtract 30 from each side.
14y = 126
Then divide each side by 14 to get what just 1 y is.
y = 9

Then to find what the other pair of opposite angle add up to subtract 156x2 from 360
156x2 = 312 360-312 = 48

Halve 48 to get the sum of just one of the opposite angles
48/2 = 24
Now you know that 3x = 24. Solve this equation
x = 8

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Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x

Radda [10]

Answer:

${\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}$

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is $\dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1$

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes are $y = k \pm \dfrac{b}{a}(x - h)$

1. Calculate h and k. The hyperbola is symmetric about the origin, so

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3

3. For 'b': The equation for the asymptote with the positive slope is

$y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x$

Thus, asymptote has the slope of

$\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}$

4. The equation of the hyperbola is

$\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}$

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0

3 years ago

Pls help with this (im not trying to be annoying)

ss7ja [257]

C(8)=29 you have to plug in 8 for n in the equation and solve. Hope this helps!!!

5 0

3 years ago

4) Durante un día de enero la temperatura bajó de 5º a -5º. ¿Cuál fue el cambio en temperatura?

mezya [45]

Temperature goes down up to 10° Celsius during the night.

Given that;

Temperature drop from 5º Celsius to -5º Celsius

Find:

Change in temperature in Celsius

Computation:

Change in temperature = Initial temperature in Celsius + Final temperature in Celsius

Change in temperature = 5 - (-5)

Change in temperature = 5 + 5

Change in temperature = 10° Celsius

Learn more:

brainly.com/question/17429019?referrer=searchResults

4 0

2 years ago

Write an expression: <br><br> The original price p of an item less a discount of 20%

Serga [27]

P-20% could be that I’m not sure I tried

8 0

3 years ago

Decrease $260 in the ratio 3:5

Marta_Voda [28]

$260 / 8 = $32.50
32.5 x 3= $97.50
32.5 x 5 = $162.50
$97.50:$162.50

4 0

3 years ago