Question

the Georgia aquarium in Atlanta is about 2.63*10^3 inches long, 1.26*10^2 inches wide, and 3*10^1 inches deep at it's largest point. Find it's approximate volume.​

Answer 1

Answer:

$9.9414*10^{6}\ cubic\ inches$

Step-by-step explanation:

Hello, I can help you with this ,

assuming the aquarium has a normal shape

The volume can be calculated with:

Volume= length*width*depth

Step one

according to the information in the question

$length\ =2.63*10^{3}\ inches \\width\ =1.26*10^{2}\ inches \\depth\ =3*10^{1}\ inches$

put the values into the equation

$Volumen=2.63*10^{3}\ inches *1.26*10^{2}\ inches *3*10^{1}\ inches$

combine similar terms

$Volumen=2.63*10^{3}\ inches *1.26*10^{2}\ inches *3*10^{1}\ inches\\Volume=(2.63*1.26*3)(10^{3}*10^{2}*10^{1})(inches *inches *inches )\\Volume=(9.9414)(10^{3+2+1})in^{3} \\Volume=(9.9414)(10^{6})in^{3}$

Have a good day.