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slega [8]
4 years ago
5

Find a positive angle less than one rotation that is coterminal of -4pi/3

Mathematics
2 answers:
Brilliant_brown [7]4 years ago
7 0
 -4pi/3 => 2pi + (-4pi/3)
-4pi/3=>6pi/3 + (-4pi/3)
-4pi/3=>2pi/3
Hope it helps :)
Setler79 [48]4 years ago
3 0

Answer:

The coterminal angle is \frac{2\pi}{3}

Step-by-step explanation:

In order to find a positive coterminal angle, we must have to add 2\pi to the angle:

2\pi + (-\frac{4\pi}{3})=2\pi -\frac{4\pi}{3}

Applying the rule for substraction of an integer and a fraction:

a-\frac{b}{c} = \frac{(a)(c)-b}{c}

In this case:

a=2\pi\\b=4\pi\\c=3

Therefore:

2\pi-\frac{4\pi}{3}=\frac{(2\pi)(3)-4\pi}{3}=\frac{6\pi-4\pi}{3}=\frac{2\pi}{3}

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We want to see if the first selection is dependent on the second selection, we will see that no, the first selection can not depend on a selection that <u>did not happen yet.</u>

So the situation is:

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Let's say that there are N puppies in total, n₁ are black, n₂ are white, such that:

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Now we have that the first selection, event A, is a black puppy. The probability is just the quotient between the number of black puppies and the total number of puppies:

q = n₁/N

Then now we have:

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Now for the second selection, event B, the probability of selecting a white puppy is:

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Notice that because there are fewer black puppies than before (because we took one) the denominator decreases, thus, the probability of getting a white puppy increases.

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Is A dependent on B?

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If you want to learn more, you can read:

brainly.com/question/12138717

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<h3><u>Part 1</u></h3>

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Since time is not negative, only one zero is meaningful:  t = 1

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<h3><u>Part 3</u></h3>

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