All you can do to solve this is isolate the y
3x+2y=9 (subtract 3x from both sides)
2y=9-3x (divide both sides by 2)
y=9/2-3/2x or y=-3/2x+9/2
Hope this helps
SAME QUESTION SOMEONE PLEASE ANSWER
Answer:
one solution
Step-by-step explanation:
3x − 7 = 4 + 6 + 4x
Combine like terms
3x-7=4x+10
Subtract 3x from each side
-7=x+10
Subtract 10 from each side
-17 =x
There is one solution
Given function is

now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into

so RHD= 
Now set both equal





k=-0.47
<u>Hence final answer is -0.47.</u>
Answer:
3,6,-2
Step-by-step explanation:
a+2a+b = 7
2a^2b = -36
a*2a + ab + 2ab = 0
or, a(2a+3b) = 0
so, b = -2a/3
Solve those and you find 3,6,-2