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Fittoniya [83]
3 years ago
8

Consider the following. (If an answer does not exist, enter DNE.) f '(x) = x2 + x − 20 (a) Find the open intervals on which f '(

x) is increasing or decreasing.
Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0

Answer:

f'(x) is increasing in the open interval (-1/2, +∞), and it is decreasing in the interval (-∞, -1/2).

Step-by-step explanation:

f'(x) is a quadratic function with positive main coefficient, then it will be decreasing until the x-coordinate of its vertex and it will be increasing from there onwards. The x-coordinate of the vertex is given by the equation -b/2a = -1/2. Hence

- f'(x) is incresing in the interval (-1/2, +∞)

- f'(x) is decreasing in the interval (-∞, -1/2)

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The best answer would be 
2.4 x 10 ^6
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irina [24]

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5 0
3 years ago
PLEASE HELP ASAP BRAINLIEST
Pachacha [2.7K]

Hi there!

The term "difference" os the result of subtracting one number from another.

So in other terms you want to know what would be the result of subtracting -4.6 from 13.5 :

13.5 - -4.6 = Difference between the two temperatures


Two minus signs turn into a positive sign so :

13.5 - -4.6 =

13.5 + 4.6 =

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Your answer is : The difference between the two temperatures is 18.1


There you go! I really hope this helped, if there's anything just let me know! :)

3 0
3 years ago
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
IRISSAK [1]

Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

3 0
3 years ago
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