Question

Mrs. Jones is creating a seating chart for the front row of her classroom. She has 10 possible students to place in the front row. If there are 30,240 different for the seating chart, how many seats are in the front row?

Answer 1

Answer:

5 seats

Step-by-step explanation:

if I'm getting the right idea, the seats are NOT enough

since the number of arrangement of 10 people in a row is

10! = 3628800 which is a lot larger than 30240.

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Let number of seats be

10PX = 30240

$\frac{10!}{(10-X)!}$ = 30240

(10-X)! = $\frac{10!}{30240}$

(10-X)! = 120

(10-X)! = 5!

10-X = 5

X = 5