All categories

3 years ago

Write the prime factorization of the number. 18,234

Mathematics

1 answer:

shusha [124]3 years ago

3 0

Answer:

$18234=2\times 3\times 3\times 1013$

Step-by-step explanation:

We are given that a number 18234

We have to find the prime factorization of the number

Prime factorization : The number written is in the product of prime numbers is called prime factorization.

In order to find the prime factorization we will find the factors of given number

$18234=2\times 3\times 3\times 1013$

Hence, the prime factorization of $18234=2\times 3\times 3\times 1013$

You might be interested in

What does the absolute value of the y coordinate tell you?

DENIUS [597]

Step-by-step explanation:

in x ,y =0

in y ,x =0

i think its thik ok dont mind if its wrong

7 0

2 years ago

Triangles MOP and MNQ are similar. Find x. 2 3 4 5

Diano4ka-milaya [45]

Answer:

x = 3

Step-by-step explanation:

MQ : MN = 5:6

MP : MO = 5:6

MQ/MN = 5/6

Hence, MP/MO = 5/6

(5+x)/(6+(18/5)) = 5/6

5+x = (5/6)(48/5)

5+x = 8

x = 3

4 0

2 years ago

A sample of an unknown liquid has a volume of 12.0 mL and a mass of 6 g. What is its density?

NemiM [27]

Density = Mass/Volume
Density = 6/12 = 0.5 g/mL or 0.5 kg/L

6 0

3 years ago

Which point is located at (6,1)? A) T B) V C) W D) X

solmaris [256]

Go 6 units in X axis and 1 unit in Y axis and you get V.

Alternative B

8 0

3 years ago

Read 2 more answers

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

2 years ago