4 years ago

Which ordered pair is the solution to the system of equations below using the elimination method?

1 answer:

7 0

15x-3y=27
5x+4y=14

multiply (2nd) equation by (3)
15x + 12y = 42

15x - 3y=27
15x + 12y = 42
-------------------substract
-15y = -15
y = 1

15x-3y=27
15x-3(1)=27
15x - 3 = 27
15x = 30
x = 2

so now you have x = 2, y =1

answer D. (2,1)

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