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3 years ago

Simplify the expression below 6m^3-16m^2+15m-40 / 2m^2+5?

1 answer:

6 0

$6m^3-16m^2+15m-40=2m^2(3m-8)+5(3m-8)=(3m-8)(2m^2+5)\\\\\dfrac{6m^3-16m^2+15m-40}{2m^2+5}=\dfrac{(3m-8)(2m^2+5)}{2m^2+5}=3m-8$

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Find the area of the rhombus. Check answer please

Vikentia [17]

Answer:

A=32 m^2.

Step-by-step explanation:

The formula for the area of a rhombus is A=pq/2.

The p is the vertical part of the rhombus and the q is the horizontal part of the rhombus.

A=(8)(8)/2.

A=64/2.

A=32 m^2

3 0

4 years ago

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ch4aika [34]

Answer:

147.5

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3 years ago

The hanger image below represent a balanced equation...Find the value of c that makes the equation true.

GarryVolchara [31]

Answer: $c = 4$

Step-by-step explanation:

For balancing a hanger,

The weight of both sides of the hanger must be equal,

Here, the left side weight = 24 unit,

While the right sides total weight = c + c + c + c + c + c

= 6 c

For balancing it,

$6 c = 24$

⇒ $c = 4$

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4 0

4 years ago

Read 2 more answers

Use integer rules to evaluate: 85 + (-96) *

grin007 [14]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ - 11}}}}}$

Step-by-step explanation:

$\sf{85 + ( - 96)}$

Multiplying positive integer and negative integer gives a negative integer i.e ( + ) × ( - ) = ( - )

$\longrightarrow{ \sf{85 - 96}}$

The negative and positive integers are always subtracted but posses the sign of the bigger integer

$\longrightarrow{ \sf{ - 11}}$

Hope I helped!

Best regards! : D

6 0

3 years ago

To allow for a models height,a designer is willing to use models that require him to change hems either up or down 2 inches.the

jenyasd209 [6]

(a)

Let's assume

the range of the lengths of the skirts is t inch

now, we are given

to change hems either up or down 2 inches

so, total change in length should be 2

so, we will have right side =2

the length of the skirts is 20 inch

this will be either greater or lesser to length of skirts

so, the difference between them will be t-20

so, we get

$|t-20|=2$

(b)

now, we can find range

firstly, we will break absolute sign

$|t-20|=-(t-20)$ for t<20

$|t-20|=(t-20)$ for t>20

because value of |t-20| must be positive

so, we get

$-(t-20)=2$

Multiply both sides by -1

$-(t-20)\times -1=2\times -1$

$(t-20)=-2$

Add both sides by 20

$(t-20)+20=-2+20$

$t=18$

$(t-20)=2$

Add both sides by 20

$(t-20)+20=2+20$

$t=22$

so, the range of the lengths of skirts is

18 in to 22 in..........Answer

(c)

Firstly, we will find difference in height of the model

5 feet 9 inches $=12\times 5+9=69in$

6 feet = $12\times 6=72in$

now, we can find difference in height

$=72-69=3in$

and we are given

difference in length of skirts =2 in

so, the difference in height is greater than the difference in length of skirts

so, the answer is NO

6 0

3 years ago