<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer:
Cos;
26 degrees
Step-by-step explanation:
Recall: SOH CAH TOA
Reference angle = y°
Adjacent side = 18 in.
Hypotenuse = 20 in.
We would apply the trigonometric function CAH since we are dealing with the Adjacent side (A) and the Hypotenuse (H). Thus:
Cos y° = Adj/Hyp
Cos y° = 18/20
Cos y° = 0.9
y° = cos^{-1}(0.9)
y = 25.8419328° ≈ 26 degrees (nearest whole degree)
The answers are:
Cos and 26 degrees
You would take d times t seconds and find the answer
<span>1/8 + 2(1/2m + 5) = 1/4m + 7 would equal m=-25/6</span>
Answer:
Step-by-step explanation:
We are given that a function
We have to find the average value of function on the given interval [1,e]
Average value of function on interval [a,b] is given by
Using the formula
By Parts integration formula
u=ln x and v=dx
Apply by parts integration
By using property lne=1,ln 1=0