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Vesna [10]
3 years ago
5

a teacher wants to know how much she can predict a student reading level in a given school district. the table shows the grade a

nd reading levels of eight student. what percent of variation in the reading level can be explained by changes in the grade level
Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0
The correct answer for this question is this one: "B. 90.7%" The percent of variation in the reading level can be explained by changes in the grade level is <u>90.7%</u>
<span>You have to compute the coefficient of correlation and then use a formula to get the explained variation.
</span>
Hope this helps answer your question. Should you have more questions, do not hesitate to post in brainly.
These are the following choices:
<span>A. 74.7%
B. 90.7%
C. 82.4%
D. 86.6%</span>
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Marcos sees a cake advertised as $15 or 2 for $25. What is the difference of the unit rate?
Mekhanik [1.2K]

Answer:

A. 2.50

Step-by-step explanation:

25 ÷ 2 = 12.5

15 - 12.5 = 2.50

6 0
3 years ago
Find the complex zeros of <br><img src="https://tex.z-dn.net/?f=%20f%28x%29%20%3D%20%7Bx%7D%5E%7B3%20%7D%20%20-%2013%20%7Bx%7D%5
timama [110]

f(x) = 0 \\\\\implies x^3-13x^2+59x -87 =0\\\\\implies x^3 -3x^2 -10x^2 +30x +29x - 87=0\\\\\implies x^2(x-3)  - 10x(x-3) + 29(x-3) =0\\\\\implies (x-3)(x^2 -10x +29) =0\\\\\implies x - 3 = 0 ~~ \text{or}~~x^2 -10x +29 = 0\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{-(-10) \pm \sqrt{(-10)^2 -4 \cdot 1 \cdot 29}}{2(1)}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm \sqrt{-16}}{2}\\\\\implies x =3~~ \text{ or} ~~ x = \dfrac{10\pm 4i }{2}\\

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6 0
3 years ago
"You measure 34 dogs' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 13.5 o
liraira [26]

Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{13.5}{\sqrt{34}} = 4.54

The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.

The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

7 0
4 years ago
Which one is right triangle angle <br>a. 45, 55 and 35<br>b. 52, 48 and 20​
Gemiola [76]
<h2>option b. 52, 48 and 20</h2>

Step-by-step explanation:

<u>let's solve:-</u>

  • To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .

soo

Pythagorean Theorem=

\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }

<h2>_____________________________________</h2>

Here:-

\bold \blue{leg \: 1 = 48} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ \bold  \blue{ leg2 = 20} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \bold\blue{hypotenuse = 52}

Putting values:-

{48}^{2}  +  {20}^{2}  = {52}^{2}   \:  \:  \:  \:  \:  \: \\  \\ 2304 + 400 = 2704 \\  \\ 2704 = 2704 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<h2>_____________________________________</h2>
4 0
3 years ago
What is the slope and the y intercept
vampirchik [111]
The slope is either 5/2 or 2/5 and the y intercept is 3
6 0
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