Answer:
1. a, 99% b71%
2. 64%, 44%
3. Number of particles 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14
frequencies: 1, 2, 3, 12, 11, 15, 18, 10, 12, 4, 5, 3, 1, 2, 1
Relative frequencies 0.01, 0.02,0.03,0.12,0.11,0.15, 0.18,0.1, 0.12,0.04, 0.05,0.03,0.01,0.02,0.01
Step-by-step explanation:
Number of particles: 0, 1, 2, 3, 4, , 5, 6, 7
Frequency: 1, 2, 3, 12, 11, 15, 18, 10
Number of particles: 8, 9, 10, 11, 12, 13, 14
Frequency: 12, 4, 5, 3, 1, 2, 1
we solve by saying that . one of th smaples wafer is with any particles. we get the proportion by subtracting 1 from the total divided by 100
100-1/100
.99
at least five particles , then we can subtract the number of those with particles less than five from 100 , divided by 100
100-(11+12+3+2+1)=71/100
0.71 or 71%
b. those particles within 5 and 10 inclusive
15+18+10+12+4+5=64/100
0.64
0r 64%
five and 10 exclusively will be
18+10+12+4=44/100
0.44
44%
c. Draw an histogram. first we have frequency table first
Number of particles 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14
frequencies: 1, 2, 3, 12, 11, 15, 18, 10, 12, 4, 5, 3, 1, 2, 1
Relative frequencies 0.01, 0.02,0.03,0.12,0.11,0.15, 0.18,0.1, 0.12,0.04, 0.05,0.03,0.01,0.02,0.01
Relative frequencies is derived by dividing each frequencies over the total frequencies
wecan say that it is unimodal or say that it is slightly positively skewed
