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irina [24]
3 years ago
6

What property comes first in 2(x+4)=6

Mathematics
2 answers:
Reil [10]3 years ago
8 0

Answer:the (c+4)

Step-by-step explanation:

That becomes before anything

victus00 [196]3 years ago
6 0
Parentheses come first, in this case it would be (x+4)
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Consider this rectangle. The perimeter is P = 2(3) + 2(6) = 18 cm. A rectangle with length 6 centimeters and width 3 centimeters
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Answer:

Consider this rectangle. The perimeter is P = 2(3) + 2(6) = 18 cm. A rectangle with length 6 centimeters and width 3 centimeters. Suppose the dimensions of the rectangle are all multiplied by 4. The new rectangle would have the dimensions . The perimeter of the new rectangle would be cm. The new perimeter will be times as large as the perimeter of the original rectangle.

Step-by-step explanation:

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Natali5045456 [20]

Answer <u>(assuming it can be in slope-intercept form)</u>:

y = -\frac{5}{12} x-\frac{5}{6}  

Step-by-step explanation:

1) First, find the slope of the line between the two points by using the slope formula, m  = \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(0)-(-5)}{(-2)-(10)} \\m = \frac{0+5}{-2-10} \\m=\frac{5}{-12}

Thus, the slope of the line is -\frac{5}{12}.

2) Next, use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line in point-slope form. Substitute values for m, x_1, and y_1 in the formula.

Since m represents the slope, substitute -\frac{5}{12} in its place. Since x_1 and y_1 represent the x and y values of one point the line intersects, choose any of the given points (it doesn't matter which one, it will equal the same thing) and substitute its x and y values into the formula as well. (I chose (-2,0), as seen below.) Then, isolate y and expand the right side in the resulting equation to find the equation of the line in slope-intercept form:

y-(0)=-\frac{5}{12} (x-(-2))\\y-0 = -\frac{5}{12} (x+2)\\y = -\frac{5}{12} x-\frac{5}{6}

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M∠1=<br><br> a) 40<br> b) 80<br> c) 160
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\angle 1 =  \frac{1}{2} (50 + 30)&#10;

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\angle 1 =  40 \textdegree
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