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Snowcat [4.5K]
3 years ago
6

What is the volume of a sphere with a diameter of 43.5 cm, rounded to the nearest tenth of a cubic centimeter?

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer

= 43098.92

Step-by-step explanation:

Good luck

i solved and got that

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The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Cels
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Answer:

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2 years ago
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

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Answer:

-2x^2+12x

Step-by-step explanation:

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Watching his children graduate from high school is most likely a long-term goal for a person of which of these ages?
salantis [7]

Answer:


Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
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