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slavikrds [6]
3 years ago
13

Galen sold tickets for his church’s carnival for a total of $2,820. Children’s tickets cost $3 each and adult tickets cost $5 ea

ch. The number of children's tickets sold was 30 more than 3 times the number of adult tickets sold. How many children’s tickets and how many adult tickets did he sell?
Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

a = 195 ; c = 615

Step-by-step explanation:

So, you want to start by forming your equations...

I will use 'c' for children and 'a' for adults for my variables

3a + 30 = c  

(this is because of the info that 30 more tickets than 3 times the amount of children's were sold than adult)

then for equation 2:

3c + 5a = 2820

(this is because of the prices of the tickets and the total money raised)

Then, plug in the equation for c

Your equation should look like:

3(3a + 30) + 5a = 2820

You get:

(9a +90) + 5a = 2820

Then:

14a = 2730

So:

a = 195 adult tickets sold

Plug in a, to find c:

3 (195) + 30 = c

585 + 30 = c

c = 615 children tickets sold

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Naddik [55]

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Fifteen is a factor of the number because both 3 and 5 are prime factors.

Step-by-step explanation:

2^3 * 3^2 * 5

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