Answer:
the scatter plots shows a positive association.
Solution :
Let
and
represents the proportions of the seeds which germinate among the seeds planted in the soil containing
and
mushroom compost by weight respectively.
To test the null hypothesis
against the alternate hypothesis
.
Let
denotes the respective sample proportions and the
represents the sample size respectively.




The test statistic can be written as :

which under
follows the standard normal distribution.
We reject
at
level of significance, if the P-value
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 

= 0.171335
Since the p-value > 0.05 and
, so we fail to reject
at
level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the
of the seeds that
with the percent of the
in the soil.
Answer:

Step-by-step explanation:
The missing parameters are:
--- Cost of marble countertops
--- Cost of retail markup
Required
The cost of marked up price
This implies that we calculate m(c(a))
We have:

can be written as:

Substitute:


Hence, the cost of marked up price is: 
Answer:
0.956
Step-by-step explanation:
X is the random variable representing the number of successes in the experiment in question;
X is represented by a binomial distribution with 5 trials and 0.18 probability of success, X~B (5, 0.18);
The probability of r successes, P(X=r), is found using the formula shown in second pic;
Working is shown in the other pic.