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2 years ago

Find the output, h, when the input, x, is -18 h = 17+x/6 h=?

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

Answer:

i think h=17

Step-by-step explanation:

-18h = 17 = xh/6

Subtract xh/6 from both sides of the equation.

-18 - xh/6 = 17

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Leto [7]

Answer:

Step-by-step explanation:

73+62=135

180-135=45

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2 years ago

2. The table shows the mass of fibres in 100 grams of each food item below. Food Mass of fibre (grams per 100 grams) Beans Bread

Andre45 [30]

Given that the amount of fiber in 100 grams of beans is 3.6 grams the amount of fiber consumed from $\mathbf{\frac{2}{3}}$ of the small tin is <u>4.8 grams</u>.

<h3>How can the amount of fiber consumed be calculated?</h3>

From the given table, we have;

Mass of fiber in 100 g of beans = 3.6 grams

Mass of beans in the small tin = 200 grams

The quantity of the beans eaten = $\frac{2}{3}$ of the small tin

Required:

The amount of fiber to consumed from eating $\frac{2}{3}$ of the small tin

Solution;

$Amount \ of \ fiber \ consumed = 200 \, g \times \dfrac{3.6 \, g}{100 \, g} \times \dfrac{2}{3} = \mathbf{4.8 \, g}$

Therefore;

The amount of fiber consumed by eating $\frac{2}{3}$ of the small tin = <u>4.8 grams</u>

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2 years ago

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1 year ago

Find the area of the parallelogram in square units.

uysha [10]

I think it’s 40
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2 years ago

Read 2 more answers

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

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3 years ago