Answer:
The width of the piece of construction paper is 12 inches.
Step-by-step explanation:
The length of the construction paper= 4 3/16 in log
⇒Length of the paper = 4.1875 inches
Let the width of the paper = w inches
The area of the paper = 50 1/4 sq. inches.
⇒Area of the paper = 50.25 sq. inches
Now, Area of the paper = LENGTH x WIDTH
or, 50.25 sq. inches = 4.1875 inches x w
⇒ w = 50.25 / 4.1875 = 12 in
or, w = 12 in
Hence, the width of the piece of construction paper is 12 inches.
Answer:
7
Step-by-step explanation:
solving algebraically:
(x = the unknown number)
(our goal is to isolate x/get x by itself)
2x + 5 = 5x - 16 {equation written out}
-2x -2x
5 = 3x - 16
+ 16 + 16
21 = 3x
÷3 ÷3
7 = x
check:
(2)(7) + 5 = (5)(7) - 16
14 + 5 = 35 - 16
19 = 19
hope this helps!!
Given :-
To find :-
- which term in this sequence is 306 .
Solution :-
<u>Common</u><u> </u><u>difference </u><u>,</u>
<u>A</u><u>s </u><u>we </u><u>know</u><u> that</u><u> </u><u>,</u>
- Tⁿ = a + (n-1)d
- 306 = -13 + (n-1)11
- 306+13 = (n-1)11
- 319/11 = n-1
- 29 = n -1
- n = 30
Answer:
-11 degrees
Step-by-step explanation:
-4-7= -11
