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3 years ago

Construct the line perpendicular to KL at point M.

Mathematics

2 answers:

guapka [62]3 years ago

5 0

Based on the options given in the picture

The one that would be the result if we construct the line that perpendicular to KL at point M would be :

picture C

hope this helps

nadezda [96]3 years ago

4 0

Answer:

Option C is correct which is the line perpendicular to KL at point M.

Step-by-step explanation:

We have given some options or pictures about the perpendicular line KL at point M.

We need to find the correct option which is true about perpendicular line.

We know that, steps of construction:

Draw a line KL.
Put the compass on the point K, and draw an arc above and below the line KL.
Do the same on the point L, and draw an arc above and below the line KL.
Draw a line, where the arcs are cut to each other, perpendicular to line KL and the point which lie on the line Kl is called point M.

Therefore, option C is correct which follows the steps of construction given above.

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2 years ago

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Hello can someone please help me with this

HACTEHA [7]

Answer:

(c) is closest to the correct answer

Step-by-step explanation:

The question answers itself: "Mr. Jones's prescription calls for 1.04 tablets PER DAY, thus the amount of tablets Mr. Jones should talk daily are 1.04. Since none of the answers in the answer set have '1.04' in them, we have to use some basic logic:

The list of answers are, a) 1.25. We can rule that one out as it is not 1.04. We can also rule out b) and d) using the same logic. Thus, by process of elimination, we are left with c) 1 O. Not only is 1.0 (or just 1) the closest number to the actual amount (1.04) but it also makes the most sense, as one cannot take .04 (or 4/100ths) of a pill.

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