Answer:
Yes. He spent 10 dollars.
Step-by-step explanation:
If he bought 10 apples, and he had 10 dollars, he would have no money left because each apple was 1 dollar.
hope this helps!
Answer:
0.66
Step-by-step explanation:
What are you giving there is a confidence interval. You can obtain a confidence interval based on a sample you got. The length of the confidence interval is determined on how much confidence do you want for your interval (the probability of the real value being inseide the interval) and how big is the sample: the bigger the sample, the smaller the length of the confidence interval. Independently of the sample length, all intervals are centered on the average value you got for the sample, and that is your estimate. In this case, the center of the interval is 0.52+0.8/2 = 0.66.
Hello!
Answer:
17 yards
Step-by-step explanation:
Hope this helps have a wonderful day! :3
Answer:
$160 hourly rate
Step-by-step explanation:
20 x 5 = 100
900 - 100 = 800
800 ÷ 5 = 160
To check: Multiply 160 by 5 and then add 100
<h2>
Answer with explanation:</h2>
Let
be the population mean lifetime of circulated $1 bills.
By considering the given information , we have :-

Since the alternative hypotheses is two tailed so the test is a two tailed test.
We assume that the lifetime of circulated $1 bills is normally distributed.
Given : Sample size : n=50 , which is greater than 30 .
It means the sample is large so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


The p-value= 
Since the p-value (0.0433834) is greater than the significance level (0.02) , so we do not reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the alternative hypothesis that the average lifetime of a circulated $1 bill differs from 18 months.