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2 years ago

Can someone help with these two questions? dont worry if its wrong!

Mathematics

2 answers:

nevsk [136]2 years ago

6 0

Answer:

1)8&3/4 CUP FLOUR

2)26 KIDS CAN GO ..

Step-by-step explanation:

1) one batch=2 1/2 cup flour

therefore batch required in 3 1/2 batch= 5/2×7/2=35/4

=8&3/4cup flour

2)No. of kids can go for $60=8

therefore,no. of kids can go in $1=8/60

Therefore,no. of kids can go in $195=8/60×195=26 kids.

gtnhenbr [62]2 years ago

6 0

<h2>Answer:</h2>

<h3>1. 8 cups of flour</h3><h3>2. 26 kids/students </h3>

________________________________

1. If one batch of cookies requires two and half cups of flour. Then we'll have to multiply it into three and a half.

<h2>Solution:</h2>

2 and half cups of flour = one batch of cookies

8 cups of flour = three batches of cookies

2. If eight kids get to go to the water park for $60. Do the same as i did on the first one. Just multiply them.

<h2>Solution:</h2>

$60 = eight kids

So every kids has to pay $7.5 to go to water park.

$7.5 × 8 = $60

$195 = 26 kids

$7.5 × 26 = $195

________________________________

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What is the approximate area of the shaded region

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That 10 is the diameter of the circle.
First let's find the area of the square.
A = s^2
Where 's' is the side.
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Step-by-step explanation:

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Use the net as an aid to compute the surface area (rounded to the nearest integer) of the triangular pyramid with an equilateral

aleksandrvk [35]

Answer:

Correct answer is $C)\ 254\ m^{2}$

Step-by-step explanation:

As per the given diagram, we know the following details:

Height of the triangular pyramid is 14m.

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Height of Triangular base = 8.7m

Formula for surface area of triangular pyramid:

$\text{Area = Area of Triangular base + 3 }\times\text{Area of side triangle}$

(Triangular base is shown in the dotted lines in the question figure.

The other 3 triangles are the side triangles.)

We know that,

$\text{Area of a triangle = }\dfrac{1}{2} \times \text{Base} \times \text{Height}$

$\Rightarrow \text{Required Surface Area = } \dfrac{1}{2} \times 8.7 \times 10 + 3 \times \dfrac{1}{2} \times 14 \times 10\\\Rightarrow \dfrac{1}{2}\times (87 + 3 \times 140)\\\Rightarrow \dfrac{1}{2}\times (87 + 420)\\\Rightarrow \dfrac{1}{2} \times 507\\$\approx$ 254 m^{2}$