Answer:
no solution
Step-by-step explanation:
n -8 = 6+n
Subtract n from each side
n-n -8 = 6+n-n
-8 = 6
This is never true so there is no solution
Given:
'a' and 'b' are the intercepts made by a straight-line with the co-
ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get



Multiply both sides by a.

The value of a is 2. So, x-intercept is 2.
Putting a=2 in
, we get


The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get

Therefore, the equation of the required line in intercept form is
.
Answer:
(√6)/2 square units
Step-by-step explanation:
The area of a triangle is half the magnitude of the cross product of the vectors representing adjacent sides.
QR = (4-3, -1-(-4), -4-(-5)) = (1, 3, 1)
QS = (3 -3, -5-(-4), -6-(-5)) = (0, -1, -1)
The cross product is the determinant ...

The magnitude of this is ...
|QR × QS| = √((-2)² +1² +(-1)²) = √6
The area of the triangle is half this value:
Area = (1/2)√6 . . . . square units