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sleet_krkn [62]
2 years ago
14

F(x) = x^2 - 3x+ 5 g(x) = 2x^2 - 4x - 11 what is h(x) = f(x) + g(x)

Mathematics
2 answers:
sashaice [31]2 years ago
6 0

Answer:

\huge\boxed{(f+g)(x)=3x^2-7x-6}

Step-by-step explanation:

f(x)=x^2-3x+5\\\\g(x)=2x^2-4x-11\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute}\\\\(f+g)(x)=(x^2-3x+5)+(2x^2-4x-11)\\\\(f+g)(x)=x^2-3x+5+2x^2-4x-11\\\\\text{combine like terms}\\\\(f+g)(x)=(x^2+2x^2)+(-3x-4x)+(5-11)\\\\(f+g)(x)=3x^2-7x-6

iogann1982 [59]2 years ago
5 0

Hey there! :)

Answer:

h(x) = 3x² - 7x - 6

Step-by-step explanation:

Calculate h(x) by adding the two polynomials:

h(x) = f(x) + g(x):

h(x) = x² - 3x + 5 + 2x² - 4x - 11

Combine like terms:

h(x) = 3x² - 7x - 6

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hopefully this helps you :)

5 0
3 years ago
Which of the numbers below belong to the solution set for x-7>3
beks73 [17]
It cant be 7 because,
X-7>3
7-7>3
0>3
And 0 is not bigger than 3

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9-7>3
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And 2 is not bigger than 3

So it is 11 because,
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11-7>3
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So the answer is 3) 11
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3 years ago
In the diagram, which letter represents the transition from gas to liquid?
Tanya [424]

Answer:

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5 0
3 years ago
How does h
Agata [3.3K]

Answer:

h(t) = 16t changes 16 units every t. in the interval t=7 to t=2,

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\int\limits^2_7 {16t} \, dt

then it's

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4 0
3 years ago
Select all the correct answers. Which two inequalities can be used to find the solution to this absolute value inequality? 3|x +
ziro4ka [17]

The absolute value inequality can be decomposed into two simpler ones.

x < 0

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<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

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Solving both of these we get:

x < 4 - 4

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These are the two inequalities.

Learn more about inequalities:

brainly.com/question/24372553

#SPJ1

6 0
9 months ago
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