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sleet_krkn [62]
3 years ago
14

F(x) = x^2 - 3x+ 5 g(x) = 2x^2 - 4x - 11 what is h(x) = f(x) + g(x)

Mathematics
2 answers:
sashaice [31]3 years ago
6 0

Answer:

\huge\boxed{(f+g)(x)=3x^2-7x-6}

Step-by-step explanation:

f(x)=x^2-3x+5\\\\g(x)=2x^2-4x-11\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute}\\\\(f+g)(x)=(x^2-3x+5)+(2x^2-4x-11)\\\\(f+g)(x)=x^2-3x+5+2x^2-4x-11\\\\\text{combine like terms}\\\\(f+g)(x)=(x^2+2x^2)+(-3x-4x)+(5-11)\\\\(f+g)(x)=3x^2-7x-6

iogann1982 [59]3 years ago
5 0

Hey there! :)

Answer:

h(x) = 3x² - 7x - 6

Step-by-step explanation:

Calculate h(x) by adding the two polynomials:

h(x) = f(x) + g(x):

h(x) = x² - 3x + 5 + 2x² - 4x - 11

Combine like terms:

h(x) = 3x² - 7x - 6

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Please help me with this :(
cupoosta [38]

Answer:

One less than 25, 24, times five is 120, and that is 4 times as much as 30 so you already know it is wrong.

Step-by-step explanation:

3 0
3 years ago
A B C or D? Multiple choice please help
S_A_V [24]

Answer: a

Step-by-step explanation:

(6z³+3z²-4z+8) - (4z²-3z+2)

all of the numbers in the second set of parenthesis are going to have their signs switched so...

(6z³+3z²-4z+8) + (-4z²+3z-2)

now you add the two sets of parenthesis

<u>6z³ - z² - z + 6</u>

<u />

7 0
3 years ago
In simple regression analysis, the standard error is ________ greater than the standard deviation of y values.
guapka [62]
In simple regression analysis, the standard error is never greater than the standard deviation of y values.
6 0
2 years ago
Can anyone someone please help me:((
Masteriza [31]

Answer:

Therefore, the standard for will be:

y=\frac{1}{4}x^{2}-x-4

Step-by-step explanation:

The equation of a parabola written as vertical axes is given by:

(x-h)^{2}=4p(y-k) (1)

The vertex of the parabola (h,k) is (2,-5).

The focus (h,k+p) is (2,-4)

Then we can find p knowing that:

h = 2

k = -5

k + p = -4 then p = -4+5 = 1

Putting all these values in equation (1) we will find the equation of the parabola:

(x-2)^{2}=4(1)(y-(-5))

(x-2)^{2}=4(y+5) (2)

Now, we need to find the standard form of the equation of the parabola.

Let's recall that standard form is:

y=ax^{2}+bx+c  

We just need to work out equation (2) to convert it to the standard form.

(x-2)^{2}=4(y+5)

x^{2}-4x+4=4(y+5)

\frac{1}{4}x^{2}-x+1=y+5

Therefore, the standard for will be:

y=\frac{1}{4}x^{2}-x-4

I hope it helps you!

 

6 0
3 years ago
In the Diagram below? DE is parallel to XY. What is the value of x?
s344n2d4d5 [400]

Answer:

x = 85

Step-by-step explanation:

If DE is parallel to XY and if DE = 85 then  XY =85

[RevyBreeze]

8 0
3 years ago
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