F(x) = x^2 - 3x+ 5 g(x) = 2x^2 - 4x - 11 what is h(x) = f(x) + g(x)

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

Answer:

$\huge\boxed{(f+g)(x)=3x^2-7x-6}$

Step-by-step explanation:

$f(x)=x^2-3x+5\\\\g(x)=2x^2-4x-11\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute}\\\\(f+g)(x)=(x^2-3x+5)+(2x^2-4x-11)\\\\(f+g)(x)=x^2-3x+5+2x^2-4x-11\\\\\text{combine like terms}\\\\(f+g)(x)=(x^2+2x^2)+(-3x-4x)+(5-11)\\\\(f+g)(x)=3x^2-7x-6$

iogann1982 [59]3 years ago

5 0

Hey there! :)

Answer:

h(x) = 3x² - 7x - 6

Step-by-step explanation:

Calculate h(x) by adding the two polynomials:

h(x) = f(x) + g(x):

h(x) = x² - 3x + 5 + 2x² - 4x - 11

Combine like terms:

h(x) = 3x² - 7x - 6

You might be interested in

the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function

Likurg_2 [28]

The function of the area of the square is A(t)=121 $t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$