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MArishka [77]
3 years ago
13

Use the given numbers above the table in multiplying integers and to fill in the blanks inside the box.​

Mathematics
2 answers:
Jet001 [13]3 years ago
8 0

Answer:

Step-by-step explanation:

1 × 5 = 5

(- 2) × (- 3) = 6

4 × (- 6) = - 24

I hope I've helped you.

azamat3 years ago
7 0

Answer:

Picture for solition......

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Answer:

see explanation

Step-by-step explanation:

- 2.3 + (- 5.7)

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A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
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Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

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