What is this and can some answer this quick

Ibrahim and Yessica have $25 in paper money and a lot of quarters and pennies. He has 22 coins and she has 14. Their coins add u

ZanzabumX [31]

Answer:

The variables are P for pennies and Q for quarters, and solving the equations we can find that they have 9 quarters and 27 pennies.

Step-by-step explanation:

We know that they have quarters and pennies, then the variables that we will use are:

P = total number of pennies

Q = total number of quarters.

Now let's solve the problem.

We know that the value of a penny is $0.01

We know that the value of a quarter is $0.25

We know that he has 22 coins, and she has 14 coins.

Then the total number of coins is 22 + 14 = 36 coins, then:

P + Q = 36

We also know that the total value of these coins is $2.52

then:

P*$0.01 + Q*$0.25 = $2.52

Then we have a system of equations:

P + Q = 36

P*$0.01 + Q*$0.25 = $2.52

To solve it, we need to start by isolate one of the variables in one of the equations, let's isolate P in the first one

P = 36 - Q

Now we can replace this in the other equation:

(36 - Q)*$0.01 + Q*$0.25 = $2.52

Now we can solve this for Q.

36*$0.01 - Q*$0.01 + Q*$0.25 = $2.52

$0.36 + Q*$0.24 = $2.52

Q*$0.24 = $2.52 - $0.36 = $2.16

Q = $2.16/$0.24 = 9

Then they have 9 quarters, and the number of pennies is given by

P = 36 - Q = 36 - 9 = 27

They have 27 pennies.

8 0

3 years ago

DIVIDING RATIONAL EXPRESSIONS

EastWind [94]

Work shown above! Answer is D hope this helps c:

7 0

4 years ago

Math help pls!! answer choices are 17.1 , 3.5 , 8.4 , and 1.5

Hoochie [10]

Triangles ABD and BCD are similar, because they are both right and share a common angle, and thus all three angles are equal.

This means that we can set the proportion

$AB\div AD = BC\div DC$

Plug the numbers and we have

$5\div 3.5 = 12\div x$

Solve for $x$ :

$x=\dfrac{12\cdot 3.5}{5}=8.4$

4 0

3 years ago

For the function G defined by G(x) = 5x + 3, find G(2)

Anon25 [30]

G(x)=5x+3

$\\ \sf\longmapsto G(2)$

$\\ \sf\longmapsto 5(2)+3$

$\\ \sf\longmapsto 10+3$

$\\ \sf\longmapsto 13$

Option c is correct

3 0

3 years ago

Read 2 more answers

Find all the solutions of the given equations in the interval [0,2pi) tan^3x=tanx and cos 3x=-cos3x

slamgirl [31]

$\tan^3x=\tan x$
$\tan^3x-\tan x=0$
$\tan x(\tan^2x-1)=0$
$\tan x(\tan x-1)(\tan x+1)=0$
$\begin{cases}\tan x=0\\\tan x-1=0\\\tan x+1=0\end{cases}$

$\tan x=\dfrac{\sin x}{\cos x}=0\implies \sin x=0\implies x=0,\pi$

$\tan x-1=0\iff\tan x=1\implies x=\dfrac\pi4,\dfrac{5\pi}4$

$\tan x+1=0\iff\tan x=-1\implies x=\dfrac{3\pi}4,\dfrac{7\pi}4$

- - -

$\cos3x=-\cos3x$
$2\cos3x=0$
$\cos3x=0\implies 3x=\dfrac\pi2,3x=\dfrac{3\pi}2\implies x=\dfrac\pi6,x=\dfrac\pi2$

This doesn't account for all the solutions, however; there are some values of $x$ that push $3x$ outside the interval $[0,2\pi)$ , so let's take a few more:

$3x=\dfrac{5\pi}2\implies x=\dfrac{5\pi}6$
$3x=\dfrac{7\pi}2\implies x=\dfrac{7\pi}6$
$3x=\dfrac{9\pi}2\implies x=\dfrac{9\pi}6$
$3x=\dfrac{11\pi}2\implies x=\dfrac{11\pi}6$

We can stop there, since the next candidate gives

$3x=\dfrac{13\pi}2\implies x=\dfrac{13\pi}6>2\pi$

7 0

3 years ago