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3 years ago

In the regression equation, what does the letter "b" represent? Select one:

Mathematics

1 answer:

dedylja [7]3 years ago

5 0

Answer:

b. The slope of the line

Step-by-step explanation:

To explain the question statement, first we view the pattern of regression of equation which is

Y=a+bx

Where Y is dependent variable and x is an independent variable.

a represents the Y-intercept and depicts the value of dependent variable y when independent variable x=0. b represents the slope in the regression equation and interpreted as unit change in dependent variable Y due to unit change in independent variable X.

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A train travels 146 miles in 2 hours. At this rate, how many miles will it travel in 3.5 hours?

Svetllana [295]

Answer:

255.5 miles

Step-by-step explanation:

146 miles - 2 hours

x miles - 3.5 hours

Cross multiply

2x = 146 x 3.5

2x = 511

Divide both sides by 2

x = 511/2

x = 255.5 miles

7 0

3 years ago

Read 2 more answers

HELPPP!! Plzzzz can’t do any more points so 10

Anestetic [448]

3. Answer: a) RT

b) XZ

c) TS

4. Answer: a) 26

b) 58

c) 21.5

d) 127

<u>Step-by-step explanation:</u>

2(PT) = AE 2(CP) = AN 2(CT) = EN

2(13) = AE 2(29) = AN 2(CT) = 43

26 = AE 58 = AN CT = 21.5

Perimeter = AE + AN + EN

= 26 + 58 + 43

= 127

4 0

3 years ago

Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

4 0

3 years ago

Please help will give medal!!!!

shepuryov [24]

If you are given with all the tree sides of the triangle, you may solve for all the angles through the Law of Cosines,
c² = a² + b² - 2ab(cos C)
where angle C is the angle opposite the side c. You may use the same equation to get the values of the remaining angle. Additionally, if you already have one known angle, you can solve for the rest of the angles by Law of Sines,
a / sin A = b / sin B = c / sin C

7 0

3 years ago

What is the limit as x is approaching 0 of the absolute value of x

vesna_86 [32]

Recall that, an absolute value expression is a piece-wise in effect, thus we'd check the single-sided limits,

$\bf \lim\limits_{x\to 0}~|x|\implies 
\begin{cases}
\lim\limits_{x\to 0^-}~-x\\\\
\lim\limits_{x\to 0^+}~+x
\end{cases}\implies 
\begin{cases}
0\\\\
0
\end{cases}\implies \lim\limits_{x\to 0}~|x|=0$

6 0

3 years ago