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PilotLPTM [1.2K]
3 years ago
9

Round 87,665 to the thousands

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0

Answer:

87.665

Step-by-step explanation:

hodyreva [135]3 years ago
3 0

Answer:

87,665 rounded to thousands is 88,000

Step-by-step explanation:

0-4 means don't round up

5-9 means round up

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Select all the equivalent to a^2/a^9 assume a doesnt equal 0
Alenkinab [10]
a ^ 2 / a ^ 9
 For this case what you should do is use the power properties to write the expression in different ways.
 Three different ways to write the expression are:
 Way 1:
 a ^ 2 / a ^ 9 = a ^ (2-9) = a ^ (- 7) = 1 / a ^ 7
 1 / a ^ 7
 Way 2:
 a ^ 2 / a ^ 9 = a ^ (2-9) = a ^ (- 7)
 a ^ (- 7)
 Way 3:
 a ^ 2 / a ^ 9 = a ^ 2 * a ^ (- 9)
 a ^ 2 * a ^ (- 9)
 Answer:
 
all the equivalent to a ^ 2 / a ^ 9 are:
 
1 / a ^ 7
 
a ^ (- 7)
 
a ^ 2 * a ^ (- 9)
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3 years ago
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How many circles are drawn in the construction of a regular hexagon?
Vinvika [58]

Answer:

C

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7 0
3 years ago
What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in
vovangra [49]
<h3>Given :</h3>
  • Distance = 175
  • Time 1 = 4 hours

\\  \\

<h3>To find:</h3>
  • Different between two speeds when distance is same.

\\  \\

<h3>Solution:</h3>

<u>Part</u><u> </u><u>1</u><u> </u><u>:</u>

In first part we will find speed 1 in which time is 4 hours

we know:-

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

So:-

\dashrightarrow\sf speed_1 =  \dfrac{distance}{time_1}

\\  \\

\dashrightarrow\sf speed_1 =  \dfrac{175}{4}

\\  \\

\dashrightarrow\bf speed_1 =  43.75 \: km {h}^{ - 1}

<u>Part 2</u>

In first part we will find speed 2 in which time is 3 hours

Again:

\bigstar \boxed{ \rm speed =  \frac{distance}{time} }

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{distance}{time_2}

\\  \\

\dashrightarrow\sf speed_2 =  \dfrac{175}{3}

\\  \\

\dashrightarrow\bf speed_2 = 58.33kmh^{-1}

\\  \\

<u>Part 3</u>

In this part we will find different between speed 1 and speed 2

\bigstar  \boxed{\rm Difference = speed_2 - speed_1}

\\  \\

So :

\dashrightarrow\sf Difference = speed_2 - speed_1 \\

\\  \\

\dashrightarrow\sf Difference =58.33 - 43.75\\

\\  \\

\dashrightarrow\bf Difference =14.58kmh^{-1}\\

\\  \\

\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}

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3 years ago
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GenaCL600 [577]

Answer:

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Step-by-step explanation:

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