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4 years ago

P(x) = 2x2 + 5x - 9 Part A Evaluate p(1.75).

Mathematics

1 answer:

Vladimir79 [104]4 years ago

4 0

Answer:

Hi there!

Your answer is:

p(1.75) = 5.875

Step-by-step explanation:

p(1.75) means to plug in 1.75 for x

p(1.75)= 2(1.75)^2 + 5(1.75) - 9

6.125 + 8.75 - 9

SIMPLIFY

5.875

Hope this helps!

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A factory that manufactures screws is performing a quality control experiment. Each object should have a length of no more than

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4 years ago

You buy a bicycle helmet for $22.26, which includes 6% sales tax. The helmet is discounted 30% off the selling price. What is th

Firdavs [7]

If you paid $22.26 after the discount and tax then 30% is 0.30 and 30% OFF is 1-0.30=0.70
Tax is 6% or 0.06 and along with the initial is 1+0.06=1.06 so P is original price in P×0.70×1.06=22.26
P×0.742=22.26
P=$30 was the original price

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3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 160

Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

$X(t) = X(0)(1-r)^{t}$

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

$X(t) = X(0)(1-r)^{t}$

$X(t) = 160(1-r)^{t}$

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

$X(t) = 160(1-r)^{t}$

$80 = 160(1-r)^{12}$

$(1 - r)^{12} = 0.5$

$\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}$

$1 - r = 0.9438$

$X(t) = 160(1-r)^{t}$

$X(t) = 160(0.9438)^{t}$

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

$X(t) = 160(0.9438)^{t}$

$2 = 160(0.9438)^{t}$

$(0.9438)^{t} = \frac{2}{160}$

$\log{(0.9438)^{t}} = \log{\frac{2}{160}}$

$t\log{0.9438} = \log{\frac{2}{160}}$

$t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}$

$t = 75.8$

It would take 75.8 minutes for the element to decay to 2 grams.

6 0

3 years ago

Five years ago Janeta age was one_fifth of her mother'sage .Now she is one_third of her mother's age.Find their present ages?

PilotLPTM [1.2K]

Answer:

J - Janeta's age M - mother's age

A) (J-5) = .2 * (M-5)

B) J = (1/3) * M

Subtracting 5 from both sides of B:

B) J -5 = (1/3)M -5

then we substitute the right side of this into the left side of A and we get

(1/3)M -5 = .2 M -1

.333333333333M -5 = .2M -1

.1111111111111111111M = 4

Mother's Age = 36

Janeta's Age = 12

Step-by-step explanation:

5 0

4 years ago

dybincka [34]

Answer: A $3.00

i did the math to get $3.00 because you need to subtract

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3 years ago