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Fed [463]
3 years ago
9

Need help plez and thanks

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0
What do u need help with
Aliun [14]3 years ago
6 0
I believe that the answer is 5 and 3
You might be interested in
Rewrite 32/35 and 9/10
hram777 [196]

The question was incorrect. Please find the correct content below.

Compare 32/35 and 9/10.

Comparing 32/35 and 9/10 we have 32/35 is greater than 9/10, that is 32/35 > 9/10.

Fraction is the ratio of two numbers. The upper number is called Numerator and the Lower number is called the Denominator.

We know that if the denominators are the same for two fractions then which has the greatest numerator is a greater fraction than the other.

Given the fractions are 32/35, 9/10

To compare this two fractions we have to make denominators equal first.

LCM of 10,35 = 70

Calculating the fractions,

32/35 = (32*2)/(35*2) = 64/70

9/10 = (9*7)/(10*7) = 63/70

Since 64 > 63

So 64/70 > 63/70

Therefore, 32/35 > 9/10

Hence fraction 32/35 is greater than the other fraction 9/10.

Learn more about Fraction here -

brainly.com/question/78672

#SPJ10

6 0
2 years ago
Pleaseeeee help im horrible at math
Murljashka [212]

Answer:

The Answer is gonna be D. 2

This is the right Answer:3

I hope you are having a great day ❤️❤️❤️

3 0
3 years ago
Read 2 more answers
Please help will give brainliest
butalik [34]

Answer:

360 m is the answer........

6 0
3 years ago
Read 2 more answers
A rectangle has a length of 12 and a width that is half the length. What is the area?
Basile [38]

Answer:

Area = length x width

width = 1/2 length = 12/2 = 6 = width

area = 6x 12 = 72

Hope that answers your question

don't hesitate to comment if you are confused about something

Step-by-step explanation:

3 0
2 years ago
The density of people (number of people per mile) during the evening rush hour for the 5 mile stretch along a certain sidewalk i
Kisachek [45]

Answer:

a.  \int\limits^5_0 {f(x)} \, dx

Step-by-step explanation:

Since f(x) is the function for the populational density at a certain sidewalk for a 5 mile stretch, a definite integral of that function will yield the total number of people within the integration intervals. If we are interested in the number of people in the whole 5 mile stretch, we must integrate f(x) from x = 0 miles to x = 5 miles:

\int\limits^5_0 {f(x)} \, dx

Therefore, the answer is alternative a.

5 0
3 years ago
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